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2a/a^2=1/3
We move all terms to the left:
2a/a^2-(1/3)=0
Domain of the equation: a^2!=0We add all the numbers together, and all the variables
a^2!=0/
a^2!=√0
a!=0
a∈R
2a/a^2-(+1/3)=0
We get rid of parentheses
2a/a^2-1/3=0
We calculate fractions
(-1a^2)/3a^2+6a/3a^2=0
We multiply all the terms by the denominator
(-1a^2)+6a=0
We get rid of parentheses
-1a^2+6a=0
a = -1; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-1)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-1}=\frac{-12}{-2} =+6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-1}=\frac{0}{-2} =0 $
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